C# – Object Oriented Programming – Lab 1 (Roots of a quadratic equation)

So I thought I’d upload some of the C# Object Oriented Programming labs I was given in my Computer Games studies and my solutions for them. Here’s the first one:

Lab1
Create a Windows Console application, with a number of variables:
a, b c (floats)
x1 and x2 (floats)
hasRoots (boolean)

The purpose of the program is to calculate the roots of the quadratic equation using the quadratic formula:

Here’s my solution for it:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace QuadraticEquation
{
class QuadraticEquation
{
static void Main(string[] args)
{
Console.Title = "The Console";
Console.WriteLine("Welcome to the console, time to solve a quadratic equation");

Console.Write("What is the value of a = ");
string aInput = Console.ReadLine();
float a = float.Parse(aInput);

Console.Write("What is the value of b = ");
string bInput = Console.ReadLine();
float b = float.Parse(bInput);

Console.Write("What is the value of c = ");
string cInput = Console.ReadLine();
float c = float.Parse(cInput);

float x1, x2;
bool hasRoots;

Console.WriteLine();
Console.WriteLine("So....");
Console.WriteLine("a is " + a);
Console.WriteLine("b is " + b);
Console.WriteLine("c is " + c);

Console.WriteLine();
Console.WriteLine("Press any key to continue");
Console.ReadKey();

float squareRootPart;
squareRootPart = (b * b) - (4 * (a * c));
double squareRooted;
squareRooted = Math.Sqrt(squareRootPart);
float floatedSquareRoot = (float)squareRooted;
x1 = (-(b) + floatedSquareRoot) / (2 * a);
x2 = (-(b) - floatedSquareRoot) / (2 * a);

Console.WriteLine();
Console.WriteLine("So the quadratic equation has the roots.." + x1 + " and " + x2);

if (x1 == 0 && x2 == 0)
{
Console.WriteLine("The quadratic equation has no real roots");
}

Console.ReadKey();
}
}
}

Lab1_Console_Quadratic.png

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